Sic Bo Results
Your results depend upon the three-dice combination. Unfortunately, most sic bo bets are really bad in terms of house edge. But Big and Small allow you to bring the house edge down to 2.78%. You should never go away from these wagers if you want the best odds of winning. Sic bo also presents a fun-and-exciting atmosphere. Live Super Sic Bo is the first dice game by Evolution Gaming, the most successful live gaming provider worldwide. The live presenter game is based on the asian ancient game of Sic Bo. In a custom built studio three dice are shaken, while you bet on the possible outcome. Sic Bo Strategy. Sic Bo is a game of luck, and therefore simply put the best strategy is to play the table layout with bets on boxes with the best odds for the player. Similar to Craps and Roulette AVOID the betting bands that have poor casino edges. Therefore the best bet to play at Sic Bo is Big/Small or Odd/Even. These boxes offer the best odds.
What is Sic Bo?
Sic Bo is particularly fascinating because of its fast – paced, and unpredictable nature, and appeals to all the casino lovers. Sic Bo literally translates to “precious dice”, and is also known by its other names, including ‘Tai Sai’, ‘Dai Siu’, ‘Big and Small’, and ‘Hi – Lo’. Three dice are kept in a dice rolling machine, with the outcome of the roll determining the winnings and losses.
Through this tutorial, you will know everything you need, to play Sic Bo on JeetWin.
Basic rules
Sic Bo is an unequal game of chance, played with three dice. While the Sic Bo table may look complex and daunting at first, once you understand the rules of the game, it is one of the most exciting games you can play on JeetWin. Three dice are kept in a dice rolling machine, and the players are then asked to bet on the results of the roll. The players may bet on the total of the three dice, the odd or even nature of the total of the three dice, the chance of a single number appearing after the roll, chances of two specific numbers appearing, or on the chance of a specific combination of numbers appearing after the roll.
Similar to roulette, you can place as many bets as you want, and each bet has a different payout, based on the probability of the number appearing on the dice.
Game Terms
On the Sic Bo table, you will find different betting areas. These would include the big and small betting areas, the odd and even betting areas, areas for different combinations of bets, single betting areas, double betting areas and finally, triple betting areas. Once you understand the betting process, the rules are simple.
Sic Bo Results Ufc
- Total Bets – In Sic Bo, you can bet on the total number shown on the three dice. You can bet on numbers ranging from 4 to 17, as 3 and 18 would constitute a triple bet. The payout on each total is different based on the probability of the numbers appearing on the dice.
- Small and Big Bets – In Sic Bo, you can bet on the probability of the total of the three dice being Small (from 4 to 10) or Big (from 11 to 17). You can bet on the total being either a Big bet, for which the total of the three dice has to be between 11 and 17, or on the chance of the total being a Small bet, for which the total of the three dice has to be between 4 and 10. It is important to note that, while Big and Small bets are considered to be the safest bets in Sic Bo, both bets would lose if a triple occurs; that is, both Big and Small lose, in case three same numbers appear on all the three dice.
- Odd and Even Bets – Players can also bet on the odd and even nature of either the total of the three dice, or on individual die. Once the croupier stops the dice rolling machine, the three numbers are revealed, and their total is calculated. Similar to Big and Small bets, odd and even bets are generally considered to be low risk bets in Sic Bo.
- Pair Bets – A pair bet in Sic Bo, is a bet which can be placed on any two specific numbers showing on the three dice after the roll. You can use the pair bet as a part of the medium risk Sic Bo strategy.
- Single Bet – In a single bet, you bet that one specific number will show on any one of the three dice. The payout for single bets is different, because one bet can win different amounts, based on how many times the number appears after the roll.
- Double Bet – In a double bet, you bet that two specific numbers will show on two of the three dice. For example, a double bet on 4 would win, if the three dice show 4, 4, 5. However, unlike a triple bet, you can only bet on a specific double, although you can bet on as many doubles as you please.
- Any Triple Bet – In a triple bet, you bet on all three dice showing the same number. The number can be non – specific, and the bet is termed as ‘Any Triple Bet’.
- Specific Triple Bet – You can also bet on the probability of all three dice showing a specific number. Specific triple bet is a part of the high risk Sic Bo strategy.
Placing Sic Bo bets
Before the dealer starts the dice rolling machine, you will hear, “Start betting”, upon which the participants place their bets on either small and big bets (3 – 17), odd and even bets, combination bets, single bet, double bet or a triple bet. The betting period closes when the dealer says, “Stop betting. No betting in this game”. The croupier then turns on the dice rolling machine, revealing the numbers on the three dice. The losing bets are then collected, and the dealer pays out the winnings.
Table Minimums & Maximums
The table limit for Sic Bo on JeetWin is Rs. 50,000,000.
1. If the participant chooses the table minimum to be Rs. 200, then the table maximum for big and small, and even and odd bets is Rs. 10,000. The table maximum for any triple bet is Rs. 333, while the table maximum for a specific triple bet is Rs. 200. The table maximum for a pair bet is Rs. 1000, while the table maximum for a single bet is Rs. 10,000. Similarly, the table maximum for a specific double bet is Rs. 2000.
You can also bet on the probability of each die showing even or odd numbers, with the table maximum for all the dice showing either even or odd numbers being Rs. 1666. Similarly, the table maximum for 2 dice showing odd numbers, while 1 die shows an even number, or vice versa is Rs. 6666.
In single bets, the table maximum for totals 4 and 17 is Rs. 200, totals 5 and 16 is Rs. 333, totals 6 and 15 is Rs. 555, totals 7 and 14 is Rs. 833, totals 8 and 13 is Rs. 1250, totals 9 and 12 is Rs. 1428, and totals 10 and 11 is Rs. 1666. The table maximum for placing 3 single bets on each die is Rs. 333, while the table maximum for placing a specific double and single bets on three dice is Rs. 200.
2.If the participant chooses the table minimum to be Rs. 300, then the table maximum for big and small, and even and odd bets is Rs. 30,000. The table maximum for any triple bet is Rs. 1,000, while the table maximum for a specific triple bet is Rs. 300. The table maximum for a pair bet is Rs. 3000, while the table maximum for a single bet is Rs. 30,000. Similarly, the table maximum for a specific double bet is Rs. 6000.
You can also bet on the probability of each die showing even or odd numbers, with the table maximum for all the dice showing either even or odd numbers being Rs. 5,000. Similarly, the table maximum for 2 dice showing odd numbers, while 1 die shows an even number, or vice versa is Rs. 20,000.
In single bets, the table maximum for totals 4 and 17 is Rs. 500, totals 5 and 16 is Rs. 1000, totals 6 and 15 is Rs. 1666, totals 7 and 14 is Rs. 2500, totals 8 and 13 is Rs. 3750, totals 9 and 12 is Rs. 4285, and totals 10 and 11 is Rs. 5000. The table maximum for placing 3 single bets on each die is Rs. 1000, while the table maximum for placing a specific double and single bets on three dice is Rs. 500.
3.If the participant chooses the table minimum to be Rs. 500, then the table maximum for big and small, and even and odd bets is Rs. 50,000. The table maximum for any triple bet is Rs. 1,666, while the table maximum for a specific triple bet is Rs. 500. The table maximum for a pair bet is Rs. 5000, while the table maximum for a single bet is Rs. 50,000. Similarly, the table maximum for a specific double bet is Rs. 10,000.
You can also bet on the probability of each die showing even or odd numbers, with the table maximum for all the dice showing either even or odd numbers being Rs. 8,333. Similarly, the table maximum for 2 dice showing odd numbers, while 1 die shows an even number, or vice versa is Rs. 33,333.
In single bets, the table maximum for totals 4 and 17 is Rs. 833, totals 5 and 16 is Rs. 1666, totals 6 and 15 is Rs. 2777, totals 7 and 14 is Rs. 4166, totals 8 and 13 is Rs. 6250, totals 9 and 12 is Rs. 7142, and totals 10 and 11 is Rs. 8333. The table maximum for placing 3 single bets on each die is Rs. 1666, while the table maximum for placing a specific double and single bets on three dice is Rs. 833.
4.If the participant chooses the table minimum to be Rs. 1,000, then the table maximum for big and small, and even and odd bets is Rs. 50,000. The table maximum for any triple bet is Rs. 1,666, while the table maximum for a specific triple bet is Rs. 1,000. The table maximum for a pair bet is Rs. 5,000, while the table maximum for a single bet is Rs. 50,000. Similarly, the table maximum for a specific double bet is Rs. 10,000.
You can also bet on the probability of each die showing even or odd numbers, with the table maximum for all the dice showing either even or odd numbers being Rs. 8,333. Similarly, the table maximum for 2 dice showing odd numbers, while 1 die shows an even number, or vice versa is Rs. 33,333.
In single bets, the table maximum for totals 4 and 17 is Rs. 1000, totals 5 and 16 is Rs. 1666, totals 6 and 15 is Rs. 2777, totals 7 and 14 is Rs. 4166, totals 8 and 13 is Rs. 6250, totals 9 and 12 is Rs. 7142, and totals 10 and 11 is Rs. 8333. The table maximum for placing 3 single bets on each die is Rs. 1666, while the table maximum for placing a specific double and single bets on three dice is Rs. 1000.
Payout Amounts
In Sic Bo, each bet has a different payout based on probability.
The payout on Big and Small bets is 1:1. That is, you essentially double the amount you bet if you win. For example, if you bet Rs. 1000 on Big and win, you will get back Rs. 2000.
Similarly, the payout on even and odd bets is 1:1. For instance, if you bet Rs. 1000 on the total being odd and win, you will get back Rs. 2000.
The payout on a pair bet is 5:1, regardless of which pair you bet on. For example, if you bet Rs. 1000 on 1 and 4 showing on two of the three dice, and the numbers on the three dice happen to be 1, 5 and 4, then you win back Rs. 6000.
The payout on a double bet is 10:1. For example, if you bet Rs. 1000 on 4 to win, and the three dice show 4, 4, and 5, then you win back Rs. 11,000.
The payout on any triple bet bet is 30:1. For example, if you bet Rs. 500 on a triple bet, and the three dice show 2, 2, and 2, then you win back Rs. 15,500.
The payout on a specific triple bet bet is 180:1. For example, if you bet Rs. 200 on three 5’s, and the three dice show 5, 5, and 5, then you win back Rs. 36,200.
The payout on a single bet depends on how many occurrences of the chosen number turn up on the three dice. If the number chosen turns up on one die, the payout is 1:1. If it turns up on two dice, the payout is 2:1, and if it turns up on all three dice, the payout is 3:1. For example, if you bet Rs. 200 on 3 showing on the dice, and the three dice show 3, 5 and 3, then you win back Rs. 600.
The payouts on each of the bets made on the three dice total differ, based on the probability of each total occurring.
- Totals of 4 and 17 have 60:1 payout.
- Totals of 5 and 16 have 30:1 payout.
- Totals of 6 and 15 have 18:1 payout.
- Totals of 7 and 14 have 12:1 payout.
- Totals of 8 and 13 have 8:1 payout.
- Totals of 9 and 12 have 7:1 payout.
- Totals of 10 and 11 have 6:1 payout.
You now have all the information you need to play Sic Bo at JeetWin! We hope you enjoy the game, and play responsibly.
The Mathematics of Sic Bo
By
Michael Shackleford
January 21, 2005
Sic Bo, meaning 'dice pair' is an ancient Chinese gambling game. Today it is one of the lesser known casino games and is often confined to designated rooms for Asian games. The game uses three dice and a table with a variety of betting options on the roll of those dice. The odds and table layout may also vary from place to place. If you must play Sic Bo I would suggest sticking to only the 'low' and 'high' bets.
Images taken from the Claridge Hotel/Casino rule book.
Following is a list of the bets available. The payoffs listed are for Atlantic City and the Mirage in Las Vegas. Other casino’s odds will vary.
- Small: Wins on total of 4-10, except for a three of a kind. Pays 1 to 1.
- Big: Wins on total of 11-17, except for a three of a kind. Pays 1 to 1.
- 4: Wins on total of 4. Pays 60 to 1.
- 5: Wins on total of 5. Pays 30 to 1.
- 6: Wins on total of 6. Pays 17 to 1.
- 7: Wins on total of 7. Pays 12 to 1.
- 8: Wins on total of 8. Pays 8 to 1.
- 9: Wins on total of 9. Pays 6 to 1.
- 10: Wins on total of 10. Pays 6 to 1.
- 11: Wins on total of 11. Pays 6 to 1.
- 12: Wins on total of 12. Pays 6 to 1.
- 13: Wins on total of 13. Pays 8 to 1.
- 14: Wins on total of 14. Pays 12 to 1.
- 15: Wins on total of 15. Pays 17 to 1.
- 16: Wins on total of 16. Pays 30 to 1.
- 17: Wins on total of 17. Pays 60 to 1.
- Two of a kind: Player may bet on any of the 15 possible two dice combinations (for example a 1 and 2). Bet wins if both numbers appear. Probability of winning is 13.89%. Pays 5 to 1.
- Double: Player may bet on any specific number (for example a 1). Player wins if at least 2 of the 3 dice land on that number. Probability of winning is 7.41%. Pays 10 to 1.
- Triple: Player may bet on any specific number (for example a 1). Player wins if all 3 dice land on that number. Probability of winning is 0.46%. Pays 180 to 1.
- Any Triple: Wins on any three of a kind. Pays 30 to 1.
- Individual Number: Player may bet on any specific number from 1 to 6. If chosen number appears 1 time bet pays 1 to 1, if it appears 2 times bet pays 2 to 1, and if it appears 3 times it pays 3 to 1.
The critical step in calculating the odds in Sic Bo is to find the probability of any given total in the throw of three dice. Following is a formula for s spots over n dice, taken from The Theory of Gambling and Statistical Logic by Richard A. Epstein, formula 5-14.
For example, let's look at the number of ways to get 11 spots over 3 dice.
int[(s-n)/6] = int[(11-3)/6] = int[1.33] = 1
The total would be 6-3 * [-10*combin(3,0)*combin(11-6*0-1,3-1) + -11*combin(3,1)*combin(11-6*1-1,3-1) ] =
1/218 * [1*1*combin(10,2) + -1*3*combin(4,2)] =
1/218 * [1*1*45 + -1*3*6] =
1/218 * [45-18] = 27/216 = 12.50%
Alternatively, if you can program a computer that would probably be the fastest way to get the results.
Here is a simple function in C++.
Following is the output of the function.
Total | Permutations | Probability |
3 | 1 | 0.00463 |
4 | 3 | 0.013889 |
5 | 6 | 0.027778 |
6 | 10 | 0.046296 |
7 | 15 | 0.069444 |
8 | 21 | 0.097222 |
9 | 25 | 0.115741 |
10 | 27 | 0.125 |
11 | 27 | 0.125 |
12 | 25 | 0.115741 |
13 | 21 | 0.097222 |
14 | 15 | 0.069444 |
15 | 10 | 0.046296 |
16 | 6 | 0.027778 |
17 | 3 | 0.013889 |
18 | 1 | 0.00463 |
If you don’t know how to program you’re going to have to do this the hard way. What I recommend is list every combination of 3 dice. To avoid the list being 63=216 items long do not repeat the same combinations in different orders. In the interests of not listing the same number twice always order each combination from lowest to highest, not forgetting combinations with a pair or three of a kind.
So we start with 1,1,1.
Next would be 1,1,2.
Then 1,1,3; 1,1,4; 1,1,5; and 1,1,6.
Obviously you can’t roll a 7 with one dice so next we increment the second die.
1,2,?
The third die must be greater or equal to the second die so the next combination in full would be 1,2,2.
Next comes 1,2,3; 1,2,4; 1,2,5; and 1,2,6.
Then comes 1,3,3.
I hope you see the pattern. The whole list would look like the following.
Low die | Medium Die | High Die |
1 | 1 | 1 |
1 | 1 | 2 |
1 | 1 | 3 |
1 | 1 | 4 |
1 | 1 | 5 |
1 | 1 | 6 |
1 | 2 | 2 |
1 | 2 | 3 |
1 | 2 | 4 |
1 | 2 | 5 |
1 | 2 | 6 |
1 | 3 | 3 |
1 | 3 | 4 |
1 | 3 | 5 |
1 | 3 | 6 |
1 | 4 | 4 |
1 | 4 | 5 |
1 | 4 | 6 |
1 | 5 | 5 |
1 | 5 | 6 |
1 | 6 | 6 |
2 | 2 | 2 |
2 | 2 | 3 |
2 | 2 | 4 |
2 | 2 | 5 |
2 | 2 | 6 |
2 | 3 | 3 |
2 | 3 | 4 |
2 | 3 | 5 |
2 | 3 | 6 |
2 | 4 | 4 |
2 | 4 | 5 |
2 | 4 | 6 |
2 | 5 | 5 |
2 | 5 | 6 |
2 | 6 | 6 |
3 | 3 | 3 |
3 | 3 | 4 |
3 | 3 | 5 |
3 | 3 | 6 |
3 | 4 | 4 |
3 | 4 | 5 |
3 | 4 | 6 |
3 | 5 | 5 |
3 | 5 | 6 |
3 | 6 | 6 |
4 | 4 | 4 |
4 | 4 | 5 |
4 | 4 | 6 |
4 | 5 | 5 |
4 | 5 | 6 |
4 | 6 | 6 |
5 | 5 | 5 |
5 | 5 | 6 |
5 | 6 | 6 |
6 | 6 | 6 |
Next we have to determine the number of permutations of each combination. A combination is a set without regard to order and a permutation is a set with regard to order.
With a three of a kind there is only one way permutation. For example if the three dice are 1,1,1 there is only one way to roll that a 1 each time.
If the combination is 1,1,2 there are three ways to roll that: 1,1,2; 1,2,1; and 2,1,1.
If all three dice are 1,2,3 there are six possible permutations: 1,2,3; 1,3,2; 2,1,3; 2,3,1; 3,1,2; 3,2,1
The general formula is that if you have a total of d dice and the totals of each number are x1, x2, x3…xn then the number of permutations are d!/(x1!*x2!*x3*…*xn). So the number of ways to get a three of a kind would be 3!/3! = 6/6 = 1. The number of ways to get a pair would be 3!/(2!*1!) = 6/(2*1) = 3. The number of ways to get three different numbers would be 3!/(1!*1!*1!) = 6/(1*1*1) = 6.
Low die | Medium die | High die | Total | Permutations |
1 | 1 | 1 | 3 | 1 |
1 | 1 | 2 | 4 | 3 |
1 | 1 | 3 | 5 | 3 |
1 | 1 | 4 | 6 | 3 |
1 | 1 | 5 | 7 | 3 |
1 | 1 | 6 | 8 | 3 |
1 | 2 | 2 | 5 | 3 |
1 | 2 | 3 | 6 | 6 |
1 | 2 | 4 | 7 | 6 |
1 | 2 | 5 | 8 | 6 |
1 | 2 | 6 | 9 | 6 |
1 | 3 | 3 | 7 | 3 |
1 | 3 | 4 | 8 | 6 |
1 | 3 | 5 | 9 | 6 |
1 | 3 | 6 | 10 | 6 |
1 | 4 | 4 | 9 | 3 |
1 | 4 | 5 | 10 | 6 |
1 | 4 | 6 | 11 | 6 |
1 | 5 | 5 | 11 | 3 |
1 | 5 | 6 | 12 | 6 |
1 | 6 | 6 | 13 | 3 |
2 | 2 | 2 | 6 | 1 |
2 | 2 | 3 | 7 | 3 |
2 | 2 | 4 | 8 | 3 |
2 | 2 | 5 | 9 | 3 |
2 | 2 | 6 | 10 | 3 |
2 | 3 | 3 | 8 | 3 |
2 | 3 | 4 | 9 | 6 |
2 | 3 | 5 | 10 | 6 |
2 | 3 | 6 | 11 | 6 |
2 | 4 | 4 | 10 | 3 |
2 | 4 | 5 | 11 | 6 |
2 | 4 | 6 | 12 | 6 |
2 | 5 | 5 | 12 | 3 |
2 | 5 | 6 | 13 | 6 |
2 | 6 | 6 | 14 | 3 |
3 | 3 | 3 | 9 | 1 |
3 | 3 | 4 | 10 | 3 |
3 | 3 | 5 | 11 | 3 |
3 | 3 | 6 | 12 | 3 |
3 | 4 | 4 | 11 | 3 |
3 | 4 | 5 | 12 | 6 |
3 | 4 | 6 | 13 | 6 |
3 | 5 | 5 | 13 | 3 |
3 | 5 | 6 | 14 | 6 |
3 | 6 | 6 | 15 | 3 |
4 | 4 | 4 | 12 | 1 |
4 | 4 | 5 | 13 | 3 |
4 | 4 | 6 | 14 | 3 |
4 | 5 | 5 | 14 | 3 |
4 | 5 | 6 | 15 | 6 |
4 | 6 | 6 | 16 | 3 |
5 | 5 | 5 | 15 | 1 |
5 | 5 | 6 | 16 | 3 |
5 | 6 | 6 | 17 | 3 |
6 | 6 | 6 | 18 | 1 |
Total | 216 |
Next we go through the tedious process of adding the number of permutations for each total. For example a total of 6 has the following combinations with the corresponding number of permutations.
Combinations | Number of Permutations |
1,1,4 | 3 |
1,2,3 | 6 |
2,2,2 | 1 |
Total | 10 |
The final table will look like this, not unlike the result of the computer function earlier.
So now lets add a column to our list for the number of combinations of each set. Let’s also add a total for the three dice.
Total | Permutations |
3 | 1 |
4 | 3 |
5 | 6 |
6 | 10 |
7 | 15 |
8 | 21 |
9 | 25 |
10 | 27 |
11 | 27 |
12 | 25 |
13 | 21 |
14 | 15 |
15 | 10 |
16 | 6 |
17 | 3 |
18 | 1 |
Total | 216 |
Now we can divide each total number permutations by the total number 3-dice permutations (216) to get the probability of each total.
Total | Permutations | Probability |
3 | 1 | 0.00463 |
4 | 3 | 0.013889 |
5 | 6 | 0.027778 |
6 | 10 | 0.046296 |
7 | 15 | 0.069444 |
8 | 21 | 0.097222 |
9 | 25 | 0.115741 |
10 | 27 | 0.125 |
11 | 27 | 0.125 |
12 | 25 | 0.115741 |
13 | 21 | 0.097222 |
14 | 15 | 0.069444 |
15 | 10 | 0.046296 |
16 | 6 | 0.027778 |
17 | 3 | 0.013889 |
18 | 1 | 0.00463 |
Total | 216 | 1 |
Finally, we are ready to evaluate the expected value of each bet. The expected value is the ratio of the amount the player can expect to win to the amount he bets on any given bet. So a fair bet would an expected value of zero. A positive expected value would mean the player has the advantage. A negative expected value would mean the dealer has the advantage.
Let’s start with the 4 bet. This wins with a total of 4 and pays 60 to 1. For those who don’t know, '60 to 1' means if the player wins he wins 60 times his bet and KEEPS his original wager. Had the odds paid '60 for 1' the player would NOT keep his original bet. Most table games pay on a 'to 1' basis.
The probability of a total of 4 is 3/216 = 0.013889. Thus the probability of losing is 1-(3/216) = 1-0.013889 = 0.986111.
The expected value of any bet with only two possibilities, winning or losing, is:
(Probability of winning)*(Amount of win) + (Probability of losing)*(Amount of loss).
For the 4 bet the expected value is
0.013889 * 60 - 0.986111*-1 = -0.15278.
So, this tells us that for every dollar the player bets on a total of 4 he can expect to lose 15.278 cents on average. Or, the house edge is 15.278%.
The next table shows the expected value and how it was calculated for all bets of a total of 4 to 17.
Total | Pays | Probability of Win | Probability of Losing | Formula of expected value | Expected Value |
4 | 60 | 0.013889 | 0.986111 | 0.0138889*60-0.986111*-1 | -0.15278 |
5 | 30 | 0.027778 | 0.972222 | 0.0277778*30-0.972222*-1 | -0.13889 |
6 | 17 | 0.046296 | 0.953704 | 0.0462963*17-0.953704*-1 | -0.16667 |
7 | 12 | 0.069444 | 0.930556 | 0.0694444*12-0.930556*-1 | -0.09722 |
8 | 8 | 0.097222 | 0.902778 | 0.0972222*8-0.902778*-1 | -0.125 |
9 | 6 | 0.115741 | 0.884259 | 0.115741*6-0.884259*-1 | -0.18981 |
10 | 6 | 0.125 | 0.875 | 0.125*6-0.875*-1 | -0.125 |
11 | 6 | 0.125 | 0.875 | 0.125*6-0.875*-1 | -0.125 |
12 | 6 | 0.115741 | 0.884259 | 0.115741*6-0.884259*-1 | -0.18981 |
13 | 8 | 0.097222 | 0.902778 | 0.0972222*8-0.902778*-1 | -0.125 |
14 | 12 | 0.069444 | 0.930556 | 0.0694444*12-0.930556*-1 | -0.09722 |
15 | 17 | 0.046296 | 0.953704 | 0.0462963*17-0.953704*-1 | -0.16667 |
16 | 30 | 0.027778 | 0.972222 | 0.0277778*30-0.972222*-1 | -0.13889 |
17 | 60 | 0.013889 | 0.986111 | 0.0138889*60-0.986111*-1 | -0.15278 |
Two of a kind
There are combin(6,2)=6!/(4!*2!)=15 ways to choose two numbers out of six. Each of these combinations is listed on the table and the player bet on as many as he wishes. If both numbers appear on the roll of the three dice then the player wins and is paid 15 to 1.
Let’s assume the player picks a 1 and 2 as his two numbers. What is the probability that both a 1 and 2 occur in the roll of 3 dice? One way to do this would be to note all the possible winning permutations:
Dice | Number of Permutations |
1,2,3 | 6 |
1,2,4 | 6 |
1,2,5 | 6 |
1,2,6 | 6 |
1,1,2 | 3 |
1,2,2 | 3 |
Total | 30 |
Thus there are a total of 30 winning permutations.
There are 63=216 total permutations, so the probability of winning is 30/216 = 1/36 = 0.1388889
The two of a kind bet pays 5 to 1. So the expected value is 0.1388889*5 + (1-0.1388889)*-1 = -0.16667. In other words the house edge is 16.67%.
Double
There are six double bets available, one for each number from 1 to 6. The player may be on any one or combination of bets. Any given bet wins if at least two of the three dice land on that number.
Let’s assume the player bets on the 1.
One way to solve it would be to note all the winning permutations:
Dice | Number of Permutations |
1,1,2 | 3 |
1,1,3 | 3 |
1,1,4 | 3 |
1,1,5 | 3 |
1,1,6 | 3 |
1,1,1 | 1 |
Total | 16 |
Thus there are a total of 16 winning permutations.
There are 63=216 total permutations, so the probability of winning is 16/216 = 0.0740741.
The double bet pays 10 to 1. So the expected value is 0.0740741*10 + (1-0.0740741)*-1 = -0.18518. In other words the house edge is 18.52% (ouch!).
Triple
Player may bet on any specific number (for example a 1). Player wins if all 3 dice land on that number.
There is obviously only one way to win this bet, so the probability of winning is 1/216 = 0.0046296. The bet pays 180 to 1 so the expected value is 0.0046296*180 + (1-0.0046296)*-1 = -0.16204. So the house edge is 16.204%.
Any Triple
The Any Triple bet pays if any three of a kind is thrown. There are obviously six winning combinations (1,1,1; 2,2,2; 3,3,3; etc.). So the probability of winning is 6/216 = 0.027778. The bet pays 30 to 1 so the expected value is 0.027778*30 + (1-0.027778)*-1 = -0.13889. So the house edge is 13.89%.
Low
The low bet wins if the total of the three dice is 3 to 10, without being a three of a kind. The probability of any total 10 or less is exactly 50%. The average number on any one die is (1+2+3+4+5+6)/6 = 21/6 = 3.5. So the average of three dice is 3*3.5 = 10.5. It stands to reason that the probability of getting under or over 10.5 is 50%.
However the bet loses on a three of a kind. There are 3 three of a kinds that would turn a winner into a loser: 1,1,1; 2,2,2; and 3,3,3. So the probability of having a total of 10 or less as a three of a kind is 3/216 = 0.0188889. So the overall probability of winning is 0.5 – 0.188889 = 0.4861111. The bet pays 1 to 1 so the expected value is 0.4861111*1 + (1-0.4861111)*-1 = -0.02778. Thus the house edge is 2.78%.
High
The high is just the opposite of the low bet, so it stands to reason the house edge would also be 2.78%.
Individual Number
Player may bet on any specific number from 1 to 6. If chosen number appears 1 time bet pays 1 to 1, if it appears 2 times bet pays 2 to 1, and if it appears 3 times it pays 3 to 1. Probability of 1 match is 34.72%, 2 matches is 6.94%, 3 matches is 0.46%.
Let’s assume the player picks the number one.
There is only one way to get three ones: 1,1,1. So the probability of three ones is 1/63 = 1/216.
Sic Bo Results 2019
Following are the ways to get two 1’s and the number of permutations of each.
Dice | Number of Permutations |
1,1,2 | 3 |
1,1,3 | 3 |
1,1,4 | 3 |
1,1,5 | 3 |
1,1,6 | 3 |
Total | 15 |
So the probability of two ones is 15/63 = 15/216.
Following are the ways to get one 1 and the number of permutations of each.
Dice | Number of Permutations |
1,2,2 | 3 |
1,2,3 | 6 |
1,2,4 | 6 |
1,2,5 | 6 |
1,2,6 | 6 |
1,3,3 | 3 |
1,3,4 | 6 |
1,3,5 | 6 |
1,3,6 | 6 |
1,4,4 | 3 |
1,4,5 | 6 |
1,4,6 | 6 |
1,5,5 | 3 |
1,5,6 | 6 |
1,6,6 | 3 |
Total | 75 |
So the probability of two ones is 75/63 = 75/216.
Another way to arrive at the probability of one 1 would be find the probability that the first die is a one and the second and third are not:
Pr(one)*Pr(not one)*Pr(not one) = (1/6)*(5/6)*(5/6) = 25/216.
However the one could appear in the first, second, or third position, so multiply by 3: 3*(25/216) = 75/216.
The probability of rolling zero ones is Pr(not one)*Pr(not one)*Pr(not one) = (5/6)*(5/6)*(5/6) = (5/6)3 = 125/216.
Sic Bo Results Football
The following return table shows the possible outcomes, and the number of combinations, probability, and return of each. The return is the product of the probability and the win or loss to the player.
Event | Permutations | Probability | Pays | Return |
Player rolls 3 ones | 1 | 0.00463 | 3 | 0.013889 |
Player rolls 2 ones | 15 | 0.069444 | 2 | 0.138889 |
Player roll 1 one | 75 | 0.347222 | 1 | 0.347222 |
Player rolls 0 ones | 125 | 0.578704 | -1 | -0.5787 |
Total | 216 | 1 | -0.0787 |
So the total expected return is -0.0787, or the house edge is 7.87%.
Sic Bo Results 2020
Sic Bo section at the Wizard of Odds.
How to calcualte the 3-dice permutation in Visual Basic.